Part - A Q1 . Let ( ) 7 2 n n f n When 1 n , 1 1 (1) 7 2 5 5 1 f Therefore the above statement is true when n =1 Assume that the above statement is true when n p i.e. ( ) 7 2 5 p p f p k ( ) k When 1 n p 1 1 ( 1) 7 2 p p f p ( 1) 7.7 2.2 p p f p ( 1) 7.(7 2 ) 5.2 p p p f p ( 1) 7.5 5.2 p f p k ( 1) 5.(7 2 ) 5 p f p k m ( ) m Therefore the above statement is true when 1 n p Hence by principle of mathematical induction the above statement is true for all n Q2 . 1, 3, 2 B A N The no. of arrangements that can be formed 6! 60 2! 3! Considering the two Ns as one, the no. of arrangements that can be formed 5! 2! 40 3! The no. of arrangements that doesn’t have two N s next to each other 60 40 20 Q3 . 3 2 i a i a i 3 1 3 2 2 a i a a i 3 1 2 , 3 2 a a i a i 1 2 3 3 2 a 3 2 3 2 2 3 i i i 2 3 2 3 2 2 3 3 2 3 i i i i i 2 3 3 1. cos sin 2 6 6 2 3 i i i i Modulus 1 , 6 Arg z AL/201 7 /10/ E - I -2 - Q4 . 3 2 2 1 ln ln 1 lim 1 x x x x x x 2 1 ( 1)( ln ln 1) lim ( 1)( 1) x x x x x x x x x 2 1 ( ln ln 1) lim ( 1) x x x x x x x 3 2 Q5 . 0 1 1 2 2 0 0 1 2 1 ( 1) ( 1) ( 1) ........ ( 1) ...... ( 1) n n n n n n n n n r r n n r n x C x C x C x C x C x Substituting for 17, 500 x n 500 500 500 0 500 499 1 500 498 2 500 500 0 1 2 500 0 500 500 17 1 17 ( 1) 17 ( 1) 17 ( 1) ........... 17 ( 1) ........... ....... 17 ( 1) r r r C C C C C 500 500 499 0 500 498 1 500 497 2 500 499 0 1 2 500 0 499 499 16 17. 17 ( 1) 17 ( 1) 17 ( 1) ........... 17 ( 1) .......... ........ 17 ( 1) 1 r r r C C C C C 2000 500 499 0 500 498 1 500 497 2 500 499 0 1 2 500 0 499 499 2 17. 17 ( 1) 17 ( 1) 17 ( 1) .............. 17 ( 1) .......... ........ 17 ( 1) 1 r r r C C C C C Multiplying both side by 3 2 , 2003 500 499 0 500 498 1 500 497 2 500 499 0 1 2 500 0 499 499 2 17. 8. 17 ( 1) 17 ( 1) 17 ( 1) ........... 17 ( 1) .......... ........ 17 ( 1) 8 r r r C C C C C The remainder when 2003 2 is divided by 17 8 Q6 . 6 4 3 A y dy 6 32 4 3 32 y 2 3 3 1 3 square units . y 6 y 4 y 2 3 y x x AL/201 7 /10/ E - I -3 - Q7 . The point at which the curve x a y be cuts y -axis 0, b Gradient of the curve at that point (0, ) b dy dx (0, ) x a b b e a b a The equation of the curve drawn at that point ( 0) b y b x a 1 x y a b The line 1 x y a b touches the curve x a y be at the point 0, b Q8 . Gradient of ON y x Gradient of PN 3 2 y x ON PN 3 1 2 y y x x ( 3) ( 2) 0 y y x x 2 2 3 13 1 2 4 x y The locus of N is a circle. Center 3 1, 2 Radius 13 2 y ( , ) N x y (2, 3) P O x AL/201 7 /10/ E - I -4 - Q9 . Equation of straight line 8 tan(135 ) 8 y x 8 8 y x 0 x y It is a line going through origin. Equation of circle 2 2 2 2 5cos 5sin x y 2 2 2 5 x y Center 0, 0 Radius 5 The circle and the straight line intersect each other. The intersecting chord is the diameter of the circle length of the chord 10 Q10 . Let 1 1 4 tan 3 , cos 5 Here , 0 2 4 2 2 , .................(1) 2 2 2 2 2 2 1 tan 1 ( 3) 4 cos(2 ) 1 tan 1 ( 3) 5 4 cos( ) cos( ) cos( ) 5 cos(2 ) cos( ) From (1) , 2 1 1 4 2 tan 3 cos 5 y 0 x y 8, 8 2 2 2 5 x y x 135 AL/201 7 /10/ E - I -5 - Part – B Q11 . ( ) ( ) a i 2 2 1 3 1 2 4 f x x x x ( ) 0 f x for all x ( ) ii 2 4 3 4 g x x m x For 0 g x , 2 0 & 4 0 a b ac 2 4 0 & 3 4 4 4 0 m 11 5 0 11 5 m m m ( ) iii 2 2 3 2 h x x m x For 0 h x , 2 0 & 4 0 a b ac 2 2 0 & 3 4 2 2 0 m 1 7 0 1 7 m m m 2 2 2 2 2 2 2 2 2 2 2 2 1 3 3 1 3 1 1 3 1 1 0 3 1 1 & 1 3 1 0 4 3 4 & 0 2 3 2 ( ) 0 & ( ) 0 11 5 & 1 7 1 5 x mx x x x x x mx x x x x x x x mx x mx x x x m x x m x g x h x m m m ( ) b 4 3 2 2 3 2 3 f x x x x x According to remainder theorem, ( 2) ( ) (2) 16 16 12 4 3 19 f x x x R f R 1 1 1 2 2 ( 2) ( ) ( 3) ( ) x x x R x x x R 1 1 2 2 1 2 2 2 2 1 ( 2) ( 2) ( ) ..............................(1) ( 2) ( 2) ( 3) ( ) ( ) ( 2) ( 3) ( ) ( 2) ( 2) f x x x x R R f x x x x x R R R f x x x x x R x R R 2 1 1 2 1 1 1 3 2 (1) ( 2) ( ) ( 2) ( 2) ( ) 2( 2) ( ) ( ) 4 6 6 2 f x x x R x R f x x x x x R f x x x x 11 5 1 7 AL/201 7 /10/ E - I -6 - The remainder take that form 1 2 2 2 2 2 2 2 32 24 12 2 42 ( ) ( 2) ( 3) ( ) ( 2) 42( 2) 19 (3) 42 19 81 54 27 6 3 44 f R f x x x x x R x f R R Remainder 2 44( 2) 42( 2) 19 x x 44, 42, 19 a b c Q12 . ( ) a 1 1 1 1 1 1 1 ( 1) 1 1 1 1 1 1 n n n n n n n n n a a a a a a a a a a 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 r r r r r r r a a a a a a a a a a 1 1 1 1 1 r r r a f r f r a a 1 ( ) 1 1 r f r a a 1 1 1 1 1 r r r r a U f r f r a a 1 2 3 1 0 1 1 2 2 3 ..... 2 1 1 n n U f f U f f U f f U f n f n U f n f n 1 1 1 1 (0) ( ) 2 1 1 1 2 1 1 n n r n n r a U f f n a a a a a 1 1 1 2 2 1 1 1 2 2 1 2 1 2 2 2 1 2 1 r n n r r n n r a 1 1 2 2 1 1 2 1 2 2 1 r n r r n r For any n , 2 0 1 2 1 n 1 1 2 0 1 1 2 1 2 0 1 1 2 1 2 n r n r r r AL/201 7 /10/ E - I -7 - 1 1 1 1 1 1 1 2017 2017 1 2017 1 2017 1 2017 2 2016 2017 1 2017 2017 2017 1 4032 2017 1 1 2017 1 2017 1 1 2017 2017 2017 1 2017 201 lim lim lim 4032 2017 1 4032 1 2017 1 2017 r n n r r n r r n n n r r r r n n n r r n n n r a 2017 7 1 4032 1 2017 n n ( ) b 2 2 2 2 ( 2) ( 1) 1; 0 2 1 ( 1) ; 0 2 y x x y x x x x or x y x x 1 2 1 2 1; 2 1 1 2 ; 2 y x y x x y x x 0 0 0 0, 2 x y y x Symmetrical axis 1 x x y 1 2 0 2 3 1 y 2 2 y x x x 1 2 y x 2 1 y x 2 2 y x x 2 2 y x x 2 3 AL/201 7 /10/ E - I -8 - 1 2 1 Intersection points of the curves 2 2 1 2 1 1 x x x x x 2 2 1 2 2 3 2 3 x x x x x 2 2 2 1 1 1 x x x x x 2 2 2 1 2 3 2 3 x x x x x 2 2 1 2 x x x The region where the curve 1 2 y x lies above 2 2 y x x Solution set 1 2 3 1 2 3 x x x x Q13 . ( ) a 1 1 0 0 1 a b a b c d c d 1 1 0 1 0 1 0 0 1 a b d b a b d b c d c a c d c a ad bc ad bc ad bc ad bc ad bc 1 1 a b d b c d c a ad bc For existence of an inverse for a 2 2 matrix, 0 ad bc 3 7 4 1 , 1 2 3 1 A B 3 7 4 1 9 4 1 2 3 1 2 1 AB 1 1 4 1 4 1 2 9 2 9 9 8 AB 1 2 7 2 7 1 1 3 1 3 6 7 A 1 1 1 1 1 1 3 4 3 4 4 3 B 1 1 1 1 1 2 7 1 1 19 26 ( ) 1 3 3 4 8 11 i A B AB A B 1 1 1 1 1 1 1 2 7 1 4 ( ) 3 4 1 3 2 9 ii B A AB B A AL /201 7 /10/ E - I -9 - ( ) b 1 3 : 4 : Im 0 : Re 0 1 3 i A i z z z z z z Let z x iy 2 2 2 2 2 4 4 4 .................................. 1 z x y x y 1 3 Im 0 1 3 1 3 Im 0 1 3 3 4 3 Im 4 3 0 4 3 .......................................... 2 i i i i x y i y x y x y x z x + iy Re 0 0.............................(3) x z (1) (2) (3) A The angle made by 3 y x with positive real-axis 1 2 tan 3 3 Area 2 1 5 4 2 6 20 3 Imaginary axis 3 y x 2 2 2 4 x y Real axis 2 3 AL/201 7 /10/ E - I -10 - ( ) c Let z x iy 2 2 2 2 2 2 ( )( ) z x y z x iy z z x iy x iy x y z ( ) ( ) 2 2Re z z x iy x iy x z 2 1 2 1 2 1 2 1 2 1 2 1 1 2 2 1 2 2 1 2 2 1 2 1 2 1 2 2 2 1 2 1 2 2 Re z z z z z z z z z z z z z z z z z z z z z z z z z z z z 2 2 2 1 2 1 2 1 2 2 2 1 2 1 2 2 Re 2 Re z z z z z z z z z z 1 2 1 2 1 2 1 2 2 2 1 2 1 2 2 2 2 2 1 2 1 2 1 2 1 2 1 2 1 2 Re 2 Re Re 0 z z z z z z z z z z z z z z z z z z z z z z 1 1 2 1 2 1 2 2 2 2 2 2 2 2 1 Re Re Re Re 0 z z z z z z z z z z z z 1 2 z z is purely imaginary. Q14 . ( ) a 2 2 2 4 x y x 2 2 2 4 4 4 ( 1) 4 4 4 0 x y x x y x x y x 2 4 0 b ac 2 4 4( 1)(4 4) 0 ( 2) 0 0 2 y y y y y 2 2 2 2 2 2 4 2 2 2 2 4 2 2 4 4 x x x x x x dy dx x x AL/201 7 /10/ E - I -11 - 0 2, 2 dy x dx Turning points : (2, 0) , ( 2, 2) ( 2, 2) is maximum point and (2, 0) is minimum point. 0 1, 0 2 x y y x Points of intersection with the axes : (0,1) , (2, 0) 2 2 2 2 2 2 4 4 1 2 4 4 4 4 4 1 x x x x x y x x x As x , 1 y Horizontal asymptote : 1 y 2 2 2 2 4 2 2 4 x x x x x y x The line y x cuts the curve at only one point. 2 2 4 2 x x x has only one real solution. ( ) b 2 2 1 2 3 V R h R H 2 2 1 1 90 00 2 3 0 2 3 3 3 H h h H 2 2 2 100 2 2 2 3 3 2 3 600 4 6 9 2 3 S Rl RH S h S h h h h 3 m H m h m AL/201 7 /10/ E - I -12 - y x y 1 y 2 1 x 2 2 dy dx 2 x 2 x 2 x 2 2 x 2 x 2 4 6 9 dS h dh h 2 2 0 4 6 0 9 5 36 6 ( 0) 5 dS h dh h h h h 6 0 5 6 0 5 dS h dh dS h dh Therefore S is minimum when 6 5 h Q15 . ( ) a sin dx ax I e bx 2 2 2 2 2 sin cos d sin cos sin d sin cos 1 sin cos ax ax ax ax ax ax ax ax ax e bx e bx b x a a e bx b e bx e bx b x a a a a e bx be bx b I a a a I ae bx be bx C a b ( ) b 2 2 2 11 3 2 3 1 3 1 1 x x A B C x x x x x 2 2 11 3 2 1 1 3 3 x x A x B x x C x 1 3 3 1 x C x A The co-efficient of o x 3 3 11 1 A B C B 2 2 2 2 2 2 11 3 2 1 1 3 3 1 3 1 1 11 3 2 1 1 3 3 1 3 1 1 x x x x x x x x x dx dx dx dx x x x x x 3 ln( 3) ln( 1) 1 x x C x C Arbitrary constant AL/201 7 /10/ E - I -13 - C Arbitrary constant ( ) c 2 2 2 2 d 1 d Ax B C x ax bx c ax bx c ax bx c 2 2 2 2 2 2 2 2 ( )(2 ) 1 ( )(2 ) 1 ax bx c A Ax B ax b C ax bx c ax bx c ax bx c ax bx c A Ax B ax b C ax bx c Co-efficient of 2 x aA Ca A C Co-efficient of x 2 2 aB Cb bC aB Co-efficient of 0 x 2 1 1 2 b Ac Bb Cc Cc C Cc a 2 2 2 2 2 , , 4 4 4 a a b C A B ac b ac b ac b 1, 4, 1 a b c 1 1 1 , , 6 3 6 A B C 2 2 2 2 1 1 1 d 1 6 3 6 d 4 1 4 1 4 1 x x x x x x x x 1 1 1 2 2 2 2 0 0 0 1 1 d 1 1 1 6 3 d 4 1 6 4 1 4 1 x dx dx dx x x x x x x x 1 1 1 2 2 2 2 0 0 0 1 1 1 d 1 1 6 3 d 4 1 6 ( 2) 3 4 1 x dx dx dx x x x x x x 1 1 1 2 2 2 0 0 0 1 1 1 1 1 1 6 3 4 1 12 3 ( 2 3) ( 2 3) 4 1 x dx dx x x x x x x 1 1 1 2 2 2 0 0 0 1 1 1 1 2 3 6 3 ln 4 1 12 3 2 3 4 1 x x dx x x x x x 1 1 1 2 2 2 0 0 0 1 1 1 3 2 3 6 3 ln 4 1 36 2 3 4 1 x x dx x x x x x 1 1 3 3 3 2 3 ln ln 12 3 36 3 3 2 3 1 3 3 3 2 3 1 3 ln ln 2 3 3 36 4 36 3 3 2 3 AL/201 7 /10/ E - I -14 - Q16 . ( ) a 2 2 2 2 0 x y gx fy c Center , g f Radius 2 2 r g f c Circle touches x -axis 2 2 2 2 r f g f c f g c Circle cuts y -axis 2 2 2 2 r g g f c g f c Length of chord 2 2 2 2 2 2 2 ( ) 2 2 r g g f c g f c Circle touches x -axis at ( , 0) a 2 2 g a c g a Length of chord 2 2 2 2 2 l a l l f c f (The circle cuts positive y -axis) Center 2 2 , 2 l a a Radius 2 2 2 l a r Equation of circle 2 2 2 2 2 2 4 4 2 4 l a l a x a y 1 12, 10 60 2 a l ABC al square units ( ) b P lies on 5 4 0 x y 5 4 0.................(1) x y Gradient of PM is m 5 ......................(2) 1 y m x (2) 5 1 (1) 5 5 1 4 0 9 25 , 5 5 9 25 , 5 5 y m x x m x m m x y m m m m P m m 3 4 4 0 x y P 5 4 0 x y Q (1,5) M y , g f r x ( , 0) A a l B C y , g f r x AL/201 7 /10/ E - I -15 - Q lies on 3 4 4 0 x y 3 4 4 0.................(1) x y Gradient of QM is m 5 ......................(2) 1 y m x (2) 5 1 (1) 3 4 5 1 4 0 4 16 15 , 4 3 4 3 4 16 15 , 4 3 4 3 y m x x m x m m x y m m m m Q m m Center of PQ is M 1 9 4 16 1 2 5 4 3 35 83 83 35 m m m m m m or 1 25 15 5 2 5 4 3 (35 83) 0 83 ( 0) 35 m m m m m m m m Equation of PQ : 83 5 ( 1) 35 83 35 92 0 y x x y Q17 . ( ) a tan tan tan 1 tan tan A B A B A B 1 1 tan 45 tan 30 3 1 3 tan15 tan 45 30 2 3 1 1 tan 45 tan 30 3 1 1 3 2 1 tan 1 tan 2 tan x x x 2 2 2 1 tan 1 sec 1 sec 1 tan tan tan 1 cos sin 2sin 2 2sin cos 2 2 tan 2 x x x R H S x x x x x x x x x L H S AL/201 7 /10/ E - I -16 - 2 2 2 1 2 3 1 1 1 tan 15 1 tan 7 2 tan15 2 3 8 4 3 1 2 3 6 2 1 2 3 ( 6 2 1)(2 3) 6 2 3 2 3 2 2 1 1 1 1 cot 7 1 2 3 2 2 1 tan 7 2 2 6 2 1 4 2 3 3 ( ) b 3 3 sin cos sin cos 1 x x x x 2 2 (sin cos )(sin cos sin cos ) sin cos 1 0 (sin cos )(1 sin cos ) sin cos 1 0 (sin cos 1)(1 sin cos ) 0 sin cos 1 sin cos 1 x x x x x x x x x x x x x x x x x x x x or x x 1 1 1 sin cos 2 2 2 x x sin 2 2 x No solution cos cos sin sin cos 4 4 4 x x cos cos 4 4 2 4 4 2 4 4 x x n n x n ( ) c Sine rule: In any ABC , sin sin in a b c A B s C Let sin sin in a b c k A B s C in sin ( ) sin in sin sin a b ks A k B i c k C s A B C AL/201 7 /10/ E - I -17 - 2 in cos 2 2 2 in cos 2 2 in cos 2 2 2 in cos 2 2 in sin 2 2 in cos 2 2 in 2 cos 2 A B A B s C C s A B C s A B C C C s A B C s C C s A B s C cos sin 2 2 C A B a b c tan tan ( ) tan tan sin sin sin sin cos cos sin sin sin cos cos sin cos sin cos sin sin sin cos sin cos sin sin( ) sin sin sin( ) sin sin( ) sin( ( )) sin sin( ) sin A B c b ii A B c A B k C k B A B A B k C A B A B B A C B A B B A C A B C B A B C A B A B B A B C C C sin( ) sin( ) sin sin sin( ) sin( ) sin 2sin cos sin (2 cos 1) 0 1 cos ( sin 0) 2 60 A B A B B B A B A B B B A B A A B A AL/201 7 /10/ E - I -18 - gFjp - A Q1 . ( ) 7 2 n n f n vd;f. 1 n ,w;F 1 1 (1) 7 2 5 5 1 f 1 n ,w;F KbT cz;ik. n p ,w;F KbT cz;ik vd;f. ( ) 7 2 5 p p f p k ( ) k 1 n p ,w;F 1 1 ( 1) 7 2 p p f p ( 1) 7.7 2.2 p p f p ( 1) 7.(7 2 ) 5.2 p p p f p ( 1) 7.5 5.2 p f p k ( 1) 5.(7 2 ) 5 p f p k m ( ) m 1 n p ,w;F KbT cz;ik. fzpj njhFj;jwpT Nfhl;ghl;bd; gb vy;yh n ,w;Fk; KbT cz;ik. Q2 . 1, 3, 2 B A N Mf;ff;$ba xOq;fikg;Gfspd; vz;zpf;if 6! 60 2! 3! ,uz;L N IAk; xd;whf fUJf. Mf;ff;$ba xOq;fikg;Gfspd; vz;zpf;if 5! 2! 40 3! ,U N ck; mLj;jLj;J ,y;yhj xOq;fikg;Gfs; 60 40 20 Q3 . 3 2 i a i a i 3 1 3 2 2 a i a a i 3 1 2 , 3 2 a a a 1 2 3 3 2 a 3 2 3 2 2 3 i i i 2 3 2 3 2 2 3 3 2 3 i i i i i 2 3 3 1. cos sin 2 6 6 2 3 i i i i kl;L 1 >; 6 Arg z AL/201 7 /10/T - I -2 -