Ex.No. 1 Date: Electricity Bill Generator Aim D evelop a Java application to generate Electricity bill. Create a class with the following members: Consumer no., consumer name, previous month reading, current month reading, and type of EB connection (i.e., domestic or commercial). Compute the bill amo unt using the following tariff. If the type of the EB connection is domestic, calculate the amount to be paid as follows: 1. First 100 units - Rs. 1 per unit 2. 101 - 200 units - Rs. 2.50 per unit 3. 201 - 500 units - Rs. 4 per unit 4. >501 units - Rs. 6 per unit If the type of the EB connection is commercial, calculate the amount to be paid as follows: 1. First 100 units - Rs. 2 per unit 2. 101 - 200 units - Rs. 4.50 per unit 3. 201 - 500 units - Rs. 6 per unit 4. >501 units - Rs. 7 per unit Source Code ElectricityBill.java import java.util.Scanner; public class ElectricityBill { private int consumerNo; private String consumerName; private int previousMonthReading; private int currentMonthReading; private String ebConnectionType; public ElectricityBill(int consumerNo, String consumerName, int previousMonthReading, int currentMonthReading, String ebConnectionType) { this.consumerNo = consumerNo; this.consumerName = consumerName; this.previousMonthReading = previousMonthReading; this.currentMonthReading = currentMonthReading; this.ebConnectionType = ebConnectionType.toLowerCase( ); } // Method to calculate the bill amount public double calculateBillAmount( ) { int unitsConsumed = currentMonthReading - previousMonthReading; double billAmount = 0; if (ebConnectionType.equals("domestic")) { billAmount = calculateDomesticBill(unitsConsumed); } else if (ebConnectionType.equals("commercial")) { billAmount = calculateCommercialBill(unitsConsumed); 2 } else { System.out.println("Invalid connection type. Please specify 'Domestic' or 'Commercial'."); } return billAmount; } private double calculateDomesticBill(int units) { if (units <= 100) { return units * 1.00; } else if (units <= 200) { return 100 * 1.00 + (units - 100) * 2.50; } else if (units <= 500) { return 100 * 1.00 + 100 * 2.50 + (units - 200) * 4.00; } else { return 100 * 1.00 + 100 * 2.50 + 300 * 4.00 + (units - 500) * 6.00; } } private double calculateCommercialBill(int units) { if (units <= 100) { return units * 2.00; } else if (units <= 200) { return 100 * 2.00 + (units - 100) * 4.50; } else if (units <= 500) { return 100 * 2.00 + 100 * 4.50 + (units - 200) * 6.00; } else { return (100 * 2.00 + 100 * 4.50 + 300 * 6.00 + (units - 500) * 7.00) - 100; } } public static void main(String[ ] args) { Scanner input = new Scanner(System.in); System.out.print("Consumer Number: "); int consumerNo = input.nextInt( ); input.nextLine( ); System.out.print("Consumer Name: "); String consumerName = input.nextLine(); System.out.print("Previous Month Reading: "); int previousMonthReading = input.nextInt(); System.out.print("Current Month Reading: "); int currentMonthReading = input.nextInt(); input.nextLine( ); System.out.print("Domestic/Commercial: "); String ebConnectionType = input.nextLine( ); // Creating ElectricityBill object with user - input data 3 ElectricityBill bill = new ElectricityBill(consumerNo, consumerName, previousMonthReading, currentMonthReading, ebConnectionType); // Calculating and displaying the bill amount double billAmount = bill.calculateBillAmount( ); System.out.println("Electricity Bill Details:"); System.out.println("Consumer Number: " + consumerNo); System.out.println("Consumer Name: " + consumerName); System.out.println("Previous Month Reading: " + previousMonthReading); System.out.println("Current Month Reading: " + currentMonthReading); System.out.println("EB Connection Type: " + ebConnectionType); System.out.println("Bill Amount: Rs. " + billAmount); input.close( ); } } Test Case - 1 User Output Consumer Number: 12345 Consumer Name: Swathi Previous Month Reading: 200 Current Month Reading: 450 Domestic/Commercial: Domestic Electricity Bill Details: Consumer Number: 12345 Consumer Name: Swathi Previous Month Reading: 200 Current Month Reading: 450 EB Connection Type: Domestic Bill Amount: Rs. 550.0 Test Case - 2 User Output Consumer Number: 2563 Consumer Name: Sangeetha Previous Month Reading: 100 Current Month Reading: 690 4 Domestic/Commercial: Commercial Electricity Bill Details: Consumer Number: 2563 Consumer Name: Sangeetha Previous Month Reading: 100 Current Month Reading: 690 EB Connection Type: Commercial Bill Amount: Rs. 2980.0 Result: The Java application for generating electricity bills executed successfully, capturing consumer details, previous and current month readings, and EB connection type, while accurately computing and displaying the final bill. 5 Ex.No. 2 Date: Kth Smallest Element Aim Write a Java program that takes an unsorted array of n integers and an integer k from the user and finds the kth smallest element in the array. The array can contain duplicate elements. Input Format: • First line is an integer n, representing the number of elements in the array. • Second line contains n integers separated by spaces, representing the elements of the array. • Third line is an integer k representing the position (1 - based index) of the element you need to find after sorting the array. Output Format: • The output is the integer which represents the kth smallest element of the array. Note: • The value of k should be a valid index within the array bounds (i.e., 1 ≤ k ≤ array length), If k is out of the bond, print "Invalid input" . • The array elements must be unique. Source Code package q42211; import java.util.Arrays; import java.util.Scanner; public class KthSmallest { public static void main(String[ ] args) { Scanner s = new Scanner(System.in); // Input the number of elements in the array int n = s.nextInt(); // Input the elements of the array int[] array = new int[n]; for (int i = 0; i < n; i++) { array[i] = s.nextInt(); } // Input the position int k = s.nextInt(); // Check if k is a valid position if (k < 1 || k > n) { System.out.println("Invalid input"); return; } // Sort the array Arrays.sort(array); // Find the k - th smallest element 6 System.out.println(array[k - 1]); s.close();} } Test Case - 1 User Output 5 5 8 9 4 6 2 5 Test Case - 2 User Output 6 14 852 625 742 351 748 8 Invalid input Result: The Java program successfully executed, taking the unsorted array and integer k as input, sorting the array while ensuring unique elements, and accurately determining and displaying the kth smallest element or an error message for invalid input. 7 Ex.No. 3 Date: Sub Array with Given Sum Aim Write a Java program to find a first continuous subarray in a given unsorted array of n non - negative integers that adds up to a specified sum S. The program should return the indices of the subarray if it exists. If no such subarray is found, it should out put that no subarray was found. Input Format: • The first line contains an integer n, the number of elements in the array. • The second line contains n space - separated integers, representing the array elements. • The third line contains an integer S, the target sum. Output Format: • If a subarray with the given sum exists, print the 0 - based starting and ending indices of the subarray. • If no such subarray is found, print No subarray. Source Code package q42212; import java.util.Scanner; public class SubarrayWithSum { public static void main(String[] args) { Scanner sc anner = new Scanner(System.in); int n = scanner.nextInt(); // Input the array elements int[] array = new int[n]; // System.out.println("Enter " + n + " space - separated integers:"); for (int i = 0; i < n; i++) { array[i] = scanner.nextInt(); } // Input the target sum // System.out.print("Enter the target sum: "); int targetSum = scanner.nextInt(); // Find the subarray with the given sum boolean subarrayFound = false; for (int start = 0; start < n; start++) { int currentSum = 0; for (int end = start; end < n; end++) { currentSum += array[end]; // Check if currentSum equals the targetSum if (currentSum == targetSum) { System.out.println(start + " " + end); subarrayFound = true; 8 break; } } if (subarrayFound) { break; } } if (!subarrayFound) { System.out.println("No subarray"); } scanner.close(); } } Test Case - 1 User Output 5 1 2 3 7 5 12 1 3 Test Case - 2 User Output 10 4 5 96 2 3 5 3 4 8 5 100 No subarray Result: The Java program executed successfully, accepting the unsorted array and target sum as input, efficiently identifying and returning the indices of the first continuous subarray matching the sum, or correctly displaying "No subarray" if no such subarray exists. 9 Ex.No. 4 Date: Matrix Addition Aim Write a Java program to add two matrices of size n×n. The program should print the r esulting matrix after addition. Input Format: • The first integer represents the size n of the square matrices. • The next n×n integers represent the elements of the first matrix. • The next n×n integers represent the elements of the second matrix. Output Format: • The resulting matrix after addition, printed in matrix form. Source Code package q42213; import java.util .Scanner; public class MatrixAddition { // write the code.. public static void main(String[] args) { Scanner sc anner = new Scanner(System.in); // Input the size of the square matrices //System.out.print("Enter the size of the square matrices (n): "); int n = scanner.nextInt(); if (n <= 0) { System.out.println("Invalid matrix size"); return; } // Input the elements of the first matrix int[][] matrix1 = new int[n][n]; //System.out.println("Enter the elements of the first matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { matrix1[i][j] = scanner.nextInt(); } } // Input the elements of the second matrix int[][] matrix2 = new int[n][n]; // System.out.println("Enter the elements of the second matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { matrix2[i][j] = scanner.nextInt(); } } 10 // Add the two matrices int[][] resultMatrix = new int[n][n]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { resultMatrix[i][j] = matrix1[i][j] + matrix2[i][j]; } } // Print the resulting matrix //System.out.println("Resulting Matrix after addition:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { System.out.print(resultMatrix[i][j] + " "); } System.out.println(); } scanner.close(); } } Test Case - 1 User Output 2 1 2 3 4 4 5 5 6 5 7 8 10 Test Case - 2 User Output 3 4 5 4 2 3 4 2 5 6 1 2 3 3 2 1 2 1 3 5 7 7 5 5 5 4 6 9 Result: The Java program executed successfully, reading the matrix size and elements, performing element - wise addition of the two n×n matrices, and correctly displaying the resulting matrix in the required format. 11 Ex.No. 5 Date: Matrix Subtraction Aim Write a Java program to subtract two square matrices of size n×n. The program should print the resu lting matrix after subtraction. Input Format: • The first integer represents the size n of the square matrices. • The next n×n integers represent the elements of the first matrix. • The next n×n integers represent the elements of the second matrix. Output Format: • The resulting matrix after subtraction, printed in matrix form. Source Code package q42214; import j ava.util.Scanner; public class MatrixSubtraction { public static void main(String[] args) { Scanner sc anner = new Scanner(System.in); // Input the size of the square matrices // System.out.print("Enter the size of the square matrices (n): "); int n = scanner.nextInt(); if (n <= 0) { System.out.println("Invalid matrix size"); return; } // Input the elements of the first matrix int[][] matrix1 = new int[n][n]; //System.out.println("Enter the elements of the first matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { matrix1[i][j] = scanner.nextInt(); } } // Input the elements of the second matrix int[][] matrix2 = new int[n][n]; //System.out.println("Enter the elements of the second matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { matrix2[i][j] = scanner.nextInt(); } } // Subtract the second matrix from the first matrix 12 int[][] resultMatrix = new int[n][n]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { resultMatrix[i][j] = matrix1[i][j] - matrix2[i][j]; } } // Print the resulting matrix // System.out.println("Resulting Matrix after subtraction:"); for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { System.out.print(resultMatrix[i][j] + " "); } System.out.println(); } scanner.close(); } } Test Case - 1 User Output 3 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 - 8 - 6 - 4 - 2 0 2 4 6 8 Test Case - 2 User Output 2 5 6 7 8 1 2 3 4 4 4 4 4 Result: The Java program executed successfully, reading the matrix size and elements, performing element - wise subtraction of the two n×n matrices, and correctly displaying the resulting matrix in the required format. 13 Ex.No. 6 Date: Matrix Multiplication Aim Write a class MultiplicationOfMatrix with a public method multiplication which returns the multiplication result of its arguments. if the first argument column size is not equal to the row size of the second argument, then the method should return null. Consider the following example for your understanding Matrix 1: Enter number of rows: 3 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 1 2 Enter row 2: 4 5 Enter row 3: 7 8 Matrix 2: Enter number of rows: 2 Enter number of columns: 3 Enter 3 numbers separated by space Enter row 1: 1 2 3 Enter row 2: 4 5 6 Multiplication of the two given matrices is: 9 12 15 24 33 42 39 54 69 Matrix 1: Enter number of rows: 2 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 1 2 Enter row 2: 3 4 Matrix 2: Enter number of rows: 3 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 1 2 Enter row 2: 4 5 Enter row 3: 2 3 Multiplication of matrices is not possible Source Code package q11106; public class MultiplicationOfMatrix{ 14 public int[][] multiplication(int[][] matrix1, int[][] matrix2) { /*Return the result if the matrix1 coloumn size is equal to matrix2 row size and print the result. * @Return null. */ // Write your logic here for matrix multiplication if (matrix1[0].length != matrix2.length) { return null; // Return null if multiplication is not possible } // Initialize the result matrix with appropriate dimensions int rows = matrix1.length; int cols = matrix2[0].length; int[][] result = new int[rows][cols]; // Perform matrix multiplication for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { result[i][j] = 0; // Initialize each element of result matrix for (int k = 0; k < matrix1[0].length; k++) { result[i][j] += matrix1[i][k] * matrix2[k][j]; } } } return result; // Return the resulting matrix } // Helper method to display a matrix public void displayMatrix(int[][] matrix) { for (int[] row : matrix) { for (int value : row) { System.out.print(value + " "); } System.out.println(); } } public static void main(String[] args) { MultiplicationOfMatrix matrixMultiplication = new MultiplicationOfMatrix(); // Example 1: Multiplication is possible int[][] matrix1 = { {1, 2}, {4, 5}, 15 {7, 8} }; int[][] matrix2 = { {1, 2, 3}, {4, 5, 6} }; int[][] result = matrixMultiplication.multiplication(matrix1, matrix2); if (result != null) { System.out.println("Multiplication of the two given matrices is:"); matrixMultiplication.displayMatrix(result); } else { System.out.println("Multiplication of matrices is not possible"); } // Example 2: Multiplication is not possible int[][] matrix3 = { {1, 2}, {3, 4} }; int[][] matrix4 = { {1, 2}, {4, 5}, {2, 3} }; result = matrixMultiplication.multiplication(matrix3, matrix4); if (result != null) { System.out.println("Multiplication of the two given matrices is:"); matrixMultiplication.displayMatrix(result); } else { System.out.println("Multiplication of matrices is not possible"); } } } package q11106; import java.util.Scanner; public class MultiplicationOfMatrixMain { public static void main(String[] args) { Scanner s = new Scanner(System.in); MultiplicationOfMatrix multiplier = new MultiplicationOfMatrix(); System.out.println("Matrix 1:"); int[][] m1 = readMatrix(s); 16 System.out.println("Matrix 2:"); int[][] m2 = readMatrix(s); int[][] multi = multiplier.multiplication(m1, m2); if (multi == null) { System.out.println("Multiplication of matrices is not possible"); } else { System.out.println("Multiplication of the two given matrices is:"); for (int i = 0; i < multi.length; i++) { int c = multi[i].length; for (int j = 0; j < c; j++) { String spacer = j == c - 1 ? " \ n" : " "; System.out.print(multi[i][j] + spacer); } } } } public static int[][] readMatrix(Scanner s) { System.out.print("Enter number of rows: "); int r = s.nextInt(); System.out.print("Enter number of columns: "); int c = s.nextInt(); int[][] m = new int[r][c]; System.out.println("Enter " + c + " numbers separated by space"); for (int i = 0; i < r; i++) { System.out.print("Enter row " + (i + 1) + ": "); for (int j = 0; j < c; j++) { m[i][j] = s.nextInt(); } } return m; } } Test Case - 1 User Output Matrix 1: Enter number of rows: 2 Enter number of columns: 3 Enter 3 numbers separated by space Enter row 1: 17 1 2 3 Enter row 2: 4 5 6 Matrix 2: Enter number of rows: 3 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 1 2 Enter row 2: 3 4 Enter row 3: 5 6 Multiplication of the two given matrices is: 22 28 49 64 Test Case - 2 User Output Matrix 1: Enter number of rows: 2 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 1 2 Enter row 2: 3 4 Matrix 2: Enter number of rows: 2 Enter number of columns: 2 Enter 2 numbers separated by space Enter row 1: 5 6 Enter row 2: 7 8 Multiplication of the two given matrices is: 19 22 43 50 Result: The Java program executed successfully, defining the MultiplicationOfMatrix class with a multiplication method that correctly computes and returns the matrix product when dimensions are compatible, or returns null when multiplication is not possible due to mismatched sizes. 18 Ex.No. 7 Date: Duplicates in Array Aim Write a Java program to remove the duplicate elements from the unsorted array Input Format: • The first line of input represents the number of elements n to be entered • The second line of input represents the n elements separated by a space Output Format: • The output should be the array with duplicates removed, preserving the order of the first occurrence of each element Source Code package q42499; import java.util.Scanner; import java.util.*; public class Duplicates { public static void main(String[] args) { Scanner sc anner = new Scanner(System.in); // Input: Number of elements int n = scanner.nextInt(); scanner.nextLine(); / / Consume the newline character // Input: Elements of the array int[] array = new int[n]; for (int i = 0; i < n; i++) { array[i] = scanner.nextInt(); } // Remove duplicates and preserve the order int[] re sult = removeDuplicates(array); // Output the result System.out.print("Array after removing duplicates: \ n"); for (int i = 0; i < result.length; i++) { System.out.print(result[i]); if (i < result.length ) { System.out.print(" "); } } System.out.println(); // Move to the next line after printing } public static int[] removeDuplicates(int[] array) { LinkedHashSet set = new LinkedHashSet<>(); // Add elements to LinkedHashSet to remove duplicates and preserve order for (int num : array) { 19 set.add(num); } // Convert the LinkedHashSet to an array int[] result = new int[set.size()]; int index = 0; for (int num : set) { result[index++] = num; } return result; } } Test Case - 1 User Output 5 1 2 3 4 4 Array after removing duplicates: 1 2 3 4 Test Case - 2 User Output 10 1 2 3 5 8 4 5 1 4 10 Array after removing duplicates: 1 2 3 5 8 4 10 Result: The Java program executed successfully, reading the number of elements and the unsorted array, removing duplicate elements while preserving the order of their first occurrence, and correctly displaying the updated array. 20 Ex.No. 8 Date: Infinite Sequence Aim Write a Java program to find the nth digit in the infinite sequence formed by concatenating all positive integers in ascending order. For example, the sequence starts as 12345678910111213... and so on. Input Format: The input consists of a single integer n, which represents the position of the digit in the infinite sequence. Output Format: The output should be a single integer which represents the nth digit in the sequence. Source Code package q42500; import java.util.Scanner; public class FindNthDigit{ public static void main(String[] args) { Scanner scanner = new Scanner(System.in); // Input the position k //System.out.print("Enter the position of the digit in the sequence: "); int k = scanner.nextInt(); // Edge case for invalid input if (k <= 0) { System.out.println("Invalid input"); return; } // Variables to keep track of digit count and number range long count = 0; // Total digits counted int digits = 1; // Current number of digits in the range long numbers = 9; // Number of numbers with 'digits' count // Find the range where the k - th digit lies while (k > count + digits * numbers) { count += digits * numbers; // Update count with digits in the current range digits++; // Move to the next digit count numbers *= 10; // Update the range to next set of numbers } // Find the actual number that contains the k - th digit long numIndex = (k - count - 1) / digits; // Index of the number in this range long digitIndex = (k - count - 1) % digits; // Index of the digit in the number // Calculate the actual number long actualNumber = (long) Math.pow(10, digits - 1) + numIndex; // First number in this

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